Question

tan^-1(tan\(\frac { 7π }{ 6 }\))

Answer 1

tan^-1(tan\(\frac { 7π }{ 6 }\)) = tan^-1tan(π + \(\frac { π }{ 6 }\) = tan^-1tan\(\frac { π }{ 6 }\)) = \(\frac { π }{ 6 }\).