Question

cot^-1(\(\sqrt{3}\))

Answer 1

Let cot^-1(\(\sqrt{3}\)) = y
∴ cot y = \(\sqrt{3}\) = cot\(\frac { π }{ 6 }\)
The range of principal value branch of cot^-1 is [0, π]
∴ principal value of cot^-1\(\sqrt{3}\) is \(\frac { π }{ 6 }\).