0 votes
149 views
in Chapter 5 Acids, Bases and Salts by (98.9k points)
edited
Write down the concentration of each of the following solutions in g/L and mol/L.  4) 4.9 g H2SO4  in 200 mL solution

1 Answer

0 votes
by (98.9k points)
selected by
 
Best answer

Given: Volume of solution = 200ml =0.2L, Mass of CH3COOH in gram =4.9g

Molecular Formula = H2SO4

Molecular mass of H2SO4 = 2(H)+1(S)+4(O) = 2 × 1 + 32 + 4 ×16 = 98m

Mass of H2SO4 in Mole (mol)

= Mass of H2SO4 in gram(g)/ Molecular mass(m)= 4.9/98 = 0.05 mol

Concentration of H2SO4 (g/L)

=Mass of solute (g)/Volume(L)  = 4.9g/0.2L = 24.5 g/L

Concentration of H2SO4 (mol/L)

= Mass of H2SO4 (mol)/Volume of H2SO4 (L)

= 0.05mol/0.2L = 0.25 mol/L

Answer is 24.5 g/L & 0.25 mol/L

Related questions

Doubtly is an online community for engineering students, offering:

  • Free viva questions PDFs
  • Previous year question papers (PYQs)
  • Academic doubt solutions
  • Expert-guided solutions

Get the pro version for free by logging in!

5.7k questions

5.1k answers

108 comments

561 users

...