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Write down the concentration of each of the following solutions in g/L and mol/L.  3) 3g CH3COOH in 100 mL solution

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Given: Volume of solution = 100ml =0.1L, Mass of CH3COOH in gram =3g

Molecular Formula = CH3COOH

Molecular mass of CH3COOH = 2(C)+2(O)+4(H) =2 × 12 + 2 × 16 + 4 × 1 = 60m

Mass of CH3COOH in Mole (mol)

= Mass of CH3COOH in gram(g)/ Molecular mass(m) = 3/60 = 0.05 mol

Concentration of CH3COOH (g/L)

=Mass of solute (g)/Volume(L) = 3g/0.1L = 30 g/L

Concentration of CH3COOH (mol/L)

= Mass of CH3COOH(mol)/Volume of CH3COOH (L)

=0.05mol/0.1L = 0.5 mol/L

Answer is 30 g/L & 0.5 mol/L

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