Given: Volume of solution = 100ml =0.1L, Mass of CH3COOH in gram =3g
Molecular Formula = CH3COOH
Molecular mass of CH3COOH = 2(C)+2(O)+4(H) =2 × 12 + 2 × 16 + 4 × 1 = 60m
Mass of CH3COOH in Mole (mol)
= Mass of CH3COOH in gram(g)/ Molecular mass(m) = 3/60 = 0.05 mol
Concentration of CH3COOH (g/L)
=Mass of solute (g)/Volume(L) = 3g/0.1L = 30 g/L
Concentration of CH3COOH (mol/L)
= Mass of CH3COOH(mol)/Volume of CH3COOH (L)
=0.05mol/0.1L = 0.5 mol/L
Answer is 30 g/L & 0.5 mol/L