Given: Volume of solution = 100ml =0.1L, Mass of Solute in gram =7.3g
Molecular Formula = HCL
Molecular mass of HCl = 1+35.5=36.5 m
Mass of HCL in Mole (mol)
= Mass of HCL in gram(g)/ Molecular mass(m) = 7.3/36.5 =0.2 mol
Concentration of HCl (g/L)
=Mass of solute (g)/Volume(L) = 7.3g/0.1L = 73 g/L
Concentration of HCL (mol/L)
=Mass of HCL in moles/Volume of HCl in L = 0.2mol/0.1L = 2 mol/L
Answer is 73 g/L & 2 mol/L