Given: Volume of solution = 50ml =0.05L, Mass of NaOH in gram =2g
Molecular Formula = NaOH
Molecular mass of NaOH = 23 +16 + 1 = 40m
Mass of HCL in Mole (mol)
= Mass of NaOH in gram(g)/ Molecular mass(m) = 2/40 =0.05 mol
Concentration of NaOH (g/L)
=Mass of solute (g)/Volume(L) = 2g/0.05L = 40 g/L
Concentration of NaOH (mol/L)
=Mass of NaOH in moles/Volume of NaOH in L = 0.05mol/0.05L = 1 mol/L
Answer is 40 g/L & 1 mol/L