Question

Consider a uniform electric field E = 3 x 10³\(\hat { i } \) N/C.
(a) What is the flux of this field through a square of 10cm on a side whose plane is parallel to the yz plane?
(b) What is the flux through the same square if the normal to its plane makes a 60° angle with the x – axis?

Answer 1

(a) E = 3 x 10³ NC^-1, r = 10 x 10^-2m
Φ = E x Area = 3 x 10³ x (10 x 10^-2)²
= 30 Nm²C^-1

(b) Φ = E x Area x cos 60° = 30 x \(\frac { 1 }{ 2 }\) = 15 Nm²C-1