​ The electric field in a region is given by with vector E = 2/5 E0 i + 3/5 E0 j with E0 = 4.0 × 10^3 N/C

Question

The electric field in a region is given by \(\vec E=\frac 25E_0\hat i+\frac35 E_0\hat j\) with E0 = 4.0 × 10³ \(\frac NC\) .The flux of this field through a rectangular surface area 0.4 m² parallel to the Y – Z plane is..........Nm²C^–1.

Answer 1

Answer is 640

ɸ = Ex A

⇒ \(\frac 25\) x 4 x 103 x 0.4

= 640