(a) If the radius of the gaussian surface is doubled, the electric flux through the new surface will still remain the same i.e. -1 x 103Nm2C-1 This is because the same charge is enclosed by the gaussian surface in the two cases.
(b) Φ = \(\frac{\mathrm{q}}{\varepsilon_{0}}\), q = \(\varepsilon_{0}\) Φ = 8.85 x 10-12 x – 1 x 103 = – 8.85 x 10-9C