Question

If sin-1 = y, then

(A) 0 ≤ y ≤ π

(B) – \(\frac { π }{ 2 }\) ≤ y ≤ \(\frac { π }{ 2 }\)

(C) 0 < y < π

(D) – \(\frac { π }{ 2 }\) < y \(\frac { π }{ 2 }\)

Answer 1

optin B

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The range of principal value branch of sin-1 is [-\(\frac { π }{ 2 }\), \(\frac { π }{ 2 }\)]

∴ if sin-1 x = y, then – \(\frac { π }{ 2 }\) ≤ y ≤ \(\frac { π }{ 2 }\)