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Cesium chloride crystallizes in cubic unit cell with Cl- ions at the corners and a Cs+ ion in the centre of the cube. How many CsCl molecules are there in the unit cell?

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Number of Cs+ ion at body centre = 1 A

Number of Cl- ions due to 8 comers = \(\frac{1}{8}×8\) = 1

Hence unit cell contains 1 CsCl molecule.

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