Cu crystallizes in fcc unit cell with edge length of 495 pm. What is the radius of Cu atom?
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Given : a = 495 pm
Radius, r = ?
For fcc structure,
Radius = r = \(\frac{a}{2\sqrt{2}}= \frac{495}{2\sqrt{2}}\) = 175pm
Ans. Radius of Cu atom = 175 pm.
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