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Cu crystallizes in fcc unit cell with edge length of 495 pm. What is the radius of Cu atom?

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Given : a = 495 pm

Radius, r = ?

For fcc structure,

Radius = r = \(\frac{a}{2\sqrt{2}}= \frac{495}{2\sqrt{2}}\) = 175pm

Ans. Radius of Cu atom = 175 pm.

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