Given : Structure of Al = Cubic close packed structure = ccp structure
Edge length of unit cell = a = 353.6 pm = 3.536 x 10-8 cm
r = ?
Number of unit cells in 1.00 cm3 of Al = ? (...V= 1.00 cm3 )
Radius of Al atom = r = \(\frac{a}{2\sqrt{2}}=\frac{353.6}{2\sqrt{2}}\) = 125 pm
Ans. Radius of Al atom = 125 pm
Volume of one unit cell = a3 = (3.536 x 10-8)3 = 4.421 x 10-23 cm3
Number of unit cells = \(\frac{V}{a^3}=\frac{1.00}{4.421×10^{-23}}\)
= 2.26 X 1022
Ans. Number of unit cells = 2.26 x 1022.