Question

Two samples ‘m’ and ‘n’ of slaked lime were obtained from two different reactions. The details about their composition are as follows: 

‘sample m’ mass : 7g

Mass of constituent oxygen : 2g

Mass of constituent calcium : 5g

‘sample n’ mass : 1.4g

Mass of constituent oxygen : 0.4g

Mass of constituent calcium : 1.0g

Which law of chemical combination does this prove? Explain.

Answer 1

Slaked lime have two samples ‘m’ and ‘n’

Sample m Mass :7g
Mass of constituent oxygen :2g
Mass of constituent calcium :5g

In sample m, the ratio of proportion of elements (calcium:oxygen) is 5:2
Ca:O =5:2 by wight

Sample n Mass :1.4g
Mass of constituent oxygen :0.4g
Mass of constituent calcium:1.0g

In sample n, the ratio of proportion of elements (calcium:oxygen) is 1.0:0.4
Ca:O =1.0:0.4 by weight  i.e.
         =10:4
         =5:2

Out of all the laws of chemical combination, this is proved by "Law Of Constant Proportion".

Law Of Constant Proportion states that "The proportion by weight of the constituent elements in various samples of compound is fixed in ratio".

On simplifying the ratio proportion by mass, we get the same values which verifies "The Law Of Constant Proportion".