Question

Two sound waves travel at a speed of 330 m/s. If their frequencies are also identical and are equal to 540 Hz, what will be the phase difference between the waves at points 3.5 m from one source and 3 m from the other if the sources are in phase?

Answer 1

Given: n₁ = n₂ = 540 Hz, v = 330 m/s

V = n x λ

∴ λ  = 330/540 = 0.61 m

Here the path difference = 3.5 – 3 = 0.5 m

∴ Phase difference = \(\frac{2π}{λ}\) x Path difference

                          = \(\frac{2π}{0.61}\) x 0.5 = 1.64 p rad