Two finite sets have m and n element respectively. The total number of subsets of first set is 112 more than the total number of sub sets of the second set. The value of m and n respectively are
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(c) 7, 4
No. of subset of first set – No of subset of second set = 112
∴ 2m – 2n = 112
∴ 2n(2m–n – 1) = 112
∴ 2n(2m–n – 1) = 24 × 7
∴ comparing n = 4
2m–n – 1 = 7
i.e. 2m–n =8
hence ,m – n = 3 , m = n + 3 = 7
m, n = 7, 4
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