In first reaction :
3.2 g of metal oxide contains 2g metal
\(\therefore\) % of metal in metal oxide is \({2\over 3.2}\times 100=62.5 \%\)
and % of oxygen in metal oxide is \({1.2\over 3.2}\times 100 =37.5\%\)
In second reaction :
2.27 g of metal oxide contains 1.42 g of metal
\(\therefore\) % of metal in metal oxide is \({1.42\over 2.27}\times 100=62.5 \%\)
and % of oxygen in metal oxide is \({0.85\over 2.27}\times 100=37.5\%\)
the percentage of metal and oxygen in both reaction is nearly same ,
according to law of definite proportion "a given compund always conatins exactly the same proportion of elements by weight"
, hence The law of definite proportion is verified by the given data
