Molar mass of MgO= (atomic mass of Mg)+(atomic mass of O)
=24+16
=40 g/mol
1) 80g of MgO
number of mol = \(Given \space mass \over Molar \space mass\)
=\({80\over 40}=2mol\)
2) 10 g of MgO
number of mol =\(Given \space mass \over Molar \space mass\)
=\({10\over 40}=0.25 mol\)