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Let A = {θ : tanθ + secθ = √2secθ} and B = {θ : secθ - tanθ = √2tanθ} be two sets then. (a) A = B (b) A ⊂ B (c) A ≠ B (d) B ⊂ A

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Let A = {θ : tanθ + secθ = √2secθ} and B = {θ : secθ - tanθ = √2tanθ} be two sets then.
(a) A = B

(b) A ⊂ B

(c) A ≠ B

(d) B ⊂ A

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Correct option is A) A=B 


Explaination:

tan θ + sec θ = √2 sec θ

sin θ = √2 – 1

sec θ – tan θ = √2 tan θ

sin θ = 1 / (√2 + 1)

sin θ = √2 – 1

A = B

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