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If A and B are events such that P(A/B) = P(B/A), then
(A) A ⊂ B
(B) B = A
(C) A ∩ B = ∅
(D) P(A) = P(B)

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(D) P(A) = P(B) is correct option :
 


P(A/B) = P(B/A)
⇒ \(\frac{P(A∩B)}{P(B)}\) = \(\frac{P(A∩B)}{P(A)}\)
⇒ P(A) = P(B)

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