Please read the guide .
Please answer the question in detail
Data: |e2| = 9.6 × 10-2 V, dI1/dt = 1.2 A/s |e2| = M\(\frac{d I_{1}}{d t}\) Mutual inductance, M = \(\frac{\left|e_{2}\right|}{d I_{1} / d t}=\frac{9.6 \times 10^{-2}}{1.2}\) = 8 × 10-2 H = 80 mH
Doubtly is an online community for engineering students, offering:
Get the pro version for free by logging in!
5.7k questions
5.1k answers
108 comments
535 users