Question

When current in a coil changes from 5 A to 2 A in 0.1 s, an average voltage of 50 V is produced. The self-inductance of the coil is:

1. 0.67 H
2. 1.67 H
3. 3 H
4. 6 H

Answer 1

Correct option is 2) 1.67H 

Explaination

EMF = \(L ×  \frac{di}{dt}\)

50 = L ×\(\frac{ (5-2)}{0.1}\) = L × 30

L = \(\frac{5}{3}\) = 1.67