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A solenoid of length π m and 5 cm in diameter has winding of 1000 turns and carries a current of 5 A. Calculate the magnetic field at its centre along the axis.

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Data: L = 3.142 m, N = 1000, I = 5A,
μ0 = 4π × 10-7 T∙m/A
The magnetic induction,
B = μ0 nI = μ0(\(\frac{N}{L}\))I
= (4π × 10-7)(\(\frac{1000}{3.142}\))(5) = \(\frac{20 \times 3.142 \times 10^{-4}}{3.142}\)
= 2 × 10-3 T

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