0 votes
141 views
in Chapter10:Magnetic Fields due to Electric Current by (2.2k points)
edited

A toroid of narrow radius of 10 cm has 1000 turns of wire. For a magnetic field of 5 × 10-2 T along its axis, how much current is required to be passed through the wire?

1 Answer

0 votes
by (2.2k points)
selected by
 
Best answer

Data : CentraI radius, r = 10 cm = 0.1 m, N = 1000,
B = 5 × 10-2 T, = 4π × 10-7 T∙m/A
The magnetic induction,
B = \(\frac{\mu_{0} N I}{2 \pi r}=\frac{\mu_{0}}{4 \pi} \frac{2 N I}{r}\)
2irr 4ir r
∴ 5 × 10-2 = 10-7 × \(\frac{2(1000) I}{0.1}\)
∴ I = \(\frac{50}{2}\) = 25A
This is the required current.

Related questions

Doubtly is an online community for engineering students, offering:

  • Free viva questions PDFs
  • Previous year question papers (PYQs)
  • Academic doubt solutions
  • Expert-guided solutions

Get the pro version for free by logging in!

5.7k questions

5.1k answers

108 comments

561 users

...