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I1 = 8.0 A I2 = 5.0 A r = 4.0 cm = 4.0 x 10-2 m l = 10 cm = 0.1 m F = \(\frac{2 \times 10^{-7} \mathrm{I}_{1} \mathrm{I}_{2} l}{\mathrm{r}}\) = \(\frac{2 \times 10^{-7} \times 8 \times 5 \times 0.1}{4 \times 10^{-2}}\) = 2 x 10-5 N (towards B)
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