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I = 35 A, r = 20 cm = 20 x 10-2 m B = \(\frac{\mu_{0} I}{2 \pi r}\) = \(\frac{4 \pi \times 10^{-7} \times 35}{2 \pi \times 20 \times 10^{-2}}\) = 3.5 x 10-5 T
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