Question

A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

Answer 1

I = 3.0 cm = 3.0 x 10^-2 m
I = 10 A
B = 0.27 T
F = BIl = 0.27 x 10 x 3 x 10^-2
= 8.1 x 10^-2 N