Let ‘r’ be the internal resistance of C. The power relation is
i2(R + r) = 53.0 But R = 19.0 and i = 1.20 A
r = \(\frac{53.0}{(1.2)^{2}}\) – 19.0 = 17.8 Ω
(a) p.d between A and B is i(R + r) = 1.2 (19 + 17.8) = 44.2 V
(b) In the absence of r, i2R + i ε = 53
ε = \(\frac{53-\mathrm{i}^{2} \mathrm{R}}{\mathrm{i}}\)
(c) Since the current is directed from left to right, terminal A is positive.