Question

Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E ∩ F) = 0.2, find P(E/F) and P(F/E).

Answer 1

P(E/F) = $\frac{E\cap F}{P(F)}$ = $\frac{0.2}{0.3}$ = $\frac{2}{3}$.

 P(F/E) = $\frac{P(E\cap F)}{P(E)}$ = $\frac{0.2}{0.6}$ = $\frac{2}{6}$ = $\frac{1}{3}$.