Question

Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E ∩ F) = 0.2, find P(E/F) and P(F/E).

Answer 1

P(E/F) = \(\frac{E∩F}{P(F)}\) = \(\frac{0.2}{0.3}\) = \(\frac{2}{3}\).

 P(F/E) = \(\frac{P(E∩F)}{P(E)}\) = \(\frac{0.2}{0.6}\) = \(\frac{2}{6}\) = \(\frac{1}{3}\).