Show that the function f : R → R given by f(x) = x³ is injective.

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asked Oct 22, 2022 in Chapter 1 Relations and Functions by HelloWorld (8.1k points)
edited Jun 29, 2023

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0 votes

answered Oct 22, 2022 by HelloWorld (8.1k points)
selected Jun 29, 2023 by HelloWorld

Best answer

f(x) = x³

⇒ f(x1) = f(x2)

⇒ x³1 = x³1

⇒ x1 = x2

⇒ f is one-one, i.e., f is injective.

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