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The correct option is B.

The dimensions of torque and work are equal. Both have dimensions as [ML2T-2] 

Explaination:

Work (W) = \(\vec{F}.\vec{s} = Fs cosθ \)
= [MLT-2][L] = [ML2T-2];

Torque \(=\vec{r}\times\vec{F}=rF\sin\theta\)

= [L] [MLT-2] = [ML2T-2]

So dimension of torque and work are same.

Video Solution ::

https://youtu.be/5tqfmi1vh0E

Doubtly · 30 May 2021 Report
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