Correct option is C ) [ L2T-2 ]
Explaination::
The velocity of light in vacuum is
c = \({1 \over {\sqrt {{\mu _0}{\varepsilon _0}} }}\)
\(\therefore[{1 \over {{\mu _0}{\varepsilon _0}}}]\) = [c2] = [L2T-2]
\(\therefore\) Dimension of \({1 \over {{\mu _0}{\varepsilon _0}}}\)= [L2T-2]