Data : d = 100 λ, D = 50.0 cm
a) The condition for maximum intensity in Young's experiment is,
d sin θ = nλ , n = 0, 1, 2...,
The angle between the central maximum and itsadjacent maximum can be determined by setting n equal to 1,
∴ d sin θ = λ
∴ θ = sin−1(λ/d )= sin−1(λ/100λ) = sin−1(1/100) = 0.9’ = 0.01571 rad
(b) The distance between these maxima on the screen is
D sin θ = D(λ/d) = 50(λ/100λ) = 0.50 cm