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Curved surface area of a cone is 251.2 cm2 and radius of its base is 8 cm. Find its slant height and perpendicular height, (π = 3.14)

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Given: Radius (r) = 8 cm, curved surface area of cone = 251.2 cm2

To find: Slant height (l) and the perpendicular height (h) of the cone

i.Curved surface area of cone = πrl

∴ 251.2 = 3.14 x 8 x l


\(l=\frac{251.2}{3.14\times 8}\)

\(=\frac{25120}{314\times 8}\)

\(=\frac{3140}{314}\)



∴ l = 10 cm

ii. Now, l2 = r2 + h2

∴ 102 = 82 + h2

∴ 100 = 64 + h2

∴ 100 – 64 = h2

∴ h2 = 36

∴ h = √36 … [Taking square root on both sides]

= 6 cm

∴ The slant height and the perpendicular height of the cone are 10 cm and 6 cm respectively.

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