e. A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s2 , calculate its speed on reaching the ground and the height of the table.
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Given: t=2s , g=10 m/s2 , u=0 , a=g , s=? , v=?
Solution :
\(s=ut+\tfrac{1}{2} gt^2\)
=\(0\times 1+ \tfrac{1}{2} (10)(1)^2\)
=\( \tfrac{1}{2} (10)\)
s= 5m
v=u+gt
=0+10*1
v=10 m/s
The answer is s= 5m and v=10 m/s
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