the final velocity is zero. We know the position is 500 and acceleration is 10
Let the initial velocity = u
final velocity = v
v= 0 m/s
s = 500 m
\(2gs=v^2-u^2\)
\(u^2= 2(10)500\) --{square root of negative }
\(u=100m/s\)
v = u + at
0 = 100 - 10 t
t = 10 s
Since it took 10 secs to go up it would take tens secs to go down thus giving us a total travel time of 20 secs.
Answer is 100 m/s 20 s