Question

A boy of mass 4 kg is standing on a piece of wood having mass 5kg . If the coefficient of friction between the wood and the floor is 0.5, the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is .........N.(Round off to the Nearest Integer)

[Take g = 10 ms–2]

Answer 1

Answer is 30

N + T = 90

T = μ N = 0.5 (90–T)

1.5 T = 45

T = 30