+1 vote
246 views
in Physics by (98.9k points)
reopened by

 A time-dependent force F = 6t acts on a particle of mass 1 kg. If the particle starts from rest, the work done by the force during the first 1 sec. will be : 

(a) 9 J

(b) 18 J

(c) 4.5 J

(d) 22 J

1 Answer

+1 vote
by (98.9k points)
selected by
 
Best answer

The correct option is c)  4.5 J 

F= 6t, m = 1Kg, u =0

Now, F=ma =m(dv/dt)=1x(dv/dt)

dv/dt = 6t

\(\int ^v_0dv =\int^1_06tdt\) 

v= 3(12– 0) = 3m/s

From work-energy theorem

W =Δ KE = ½ m(v2 – u2)

W = ½ x 1(32 – 0) = 4.5 J

Related questions

Doubtly is an online community for engineering students, offering:

  • Free viva questions PDFs
  • Previous year question papers (PYQs)
  • Academic doubt solutions
  • Expert-guided solutions

Get the pro version for free by logging in!

5.7k questions

5.1k answers

108 comments

563 users

...