A system releases 125 kJ of heat while 104 kJ of work is done on the system. Calculate the change in internal energy.
Please read the guide .
Please answer the question in detail
Given: Q = −125kJ, W= −104kJ
ΔU = Q − W= −125−(−104)
= (−125 + 104) = −21kJ. Negative sign shows that decrease in energy.
This is the change (decrease) in the internal energy.
Doubtly is an online community for engineering students, offering:
Get the pro version for free by logging in!
5.7k questions
5.1k answers
108 comments
561 users