Question

A hypothetical thermodynamic cycle is shown in the figure. Calculate the work done in 25 cycles.

Answer 1

Given : a = \(\frac{ΔV_{max}}{2}=\frac{6-2}{2}×10^{-3}m^3\)  = 2 x 10⁻³ m³,

b = \(\frac{ΔP_{max}}{2}=\frac{11-1}{2}×10^{5}Pa\) = 5 x 10⁵ Pa

Cycles = 25

The work done in one cycle, \(\oint PdV\)

= πab = (3.142) (2 x 10⁻³) (5 x 10⁵)

= 3.142 x 10³J

Hence, the work done in 25 cycles

= (25) (3.142 x 10³) = 7.855 x 10⁴J

This is the work done in 25 cycles