Given : atomic mass of I=127 u
A. 254 u of iodine (I)
Formula : number of atoms = \(given \space atomic \space mass \space of \space element\over atomic \space mass \space of \space element\)
\(\therefore \space ={254\over 127}\)
=2 atoms
254 u of iodine (I) consist of 2 atoms of I
B. 254 g of iodine (I)
we know the Molar mass of iodine which is 127 g
Formula :: no of moles =\(given\space mass\over molar \space mass\)
\(\therefore\space = {254\over 127 }=2\) moles
therefore , number of atoms = n× Avogadro's number
=2\(\times 6.022\times 10^{23}\) atoms =\(1.2044\times 10^{24} atoms\)
254 g of iodine (I) consist of \(1.2044\times 10^{24} atoms\)
