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The sum of two numbers is 40 and the greater number is thrice the smaller number. Find the numbers.

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Let's solve the problem step by step:

Let the smaller number be 'x' and the greater number be 'y'.

Given information:

  • The sum of two numbers is 40: x + y = 40.
  • The greater number is thrice the smaller number: y = 3x.

We can form two equations based on the given information:

Equation 1: x + y = 40 Equation 2: y = 3x

Substitute y = 3x from Equation 2 into Equation 1: x + 3x = 40

Combine like terms: 4x = 40

Divide both sides of the equation by 4: x = 40 / 4

Simplify: x = 10

Substitute x = 10 into Equation 2 to find the value of y: y = 3(10)

Simplify: y = 30

Therefore, the smaller number is 10 and the greater number is 30.

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