If E and G respectively denote energy and gravitational constant, then E /G has the dimensions of:

Question

If E and G respectively denote energy and gravitational constant, then \(E\over G\) has the dimensions of: 

Answer 1

Correct answer: (2) [M²] [L^-1] [T⁰]

Explanation:

E = energy = [ML²T^-2]

G = Gravitational constant = [M^-1L³T^-2]

So \(\frac{E}{G} = \frac{[E]}{[G]}\)

= \(ML^2T^{−2}\over M^{−1}L^3T^{−2}\) = [M²] [L^-1] [T⁰]