Let Ui = 1 Xi for i ∈ 50 = Ui = 1 for i ∈ n Yi = T, where each Xi contains 10 elements and each Yi contains 5 elements. If each element of the set T is an element of exactly 20 of sets Xi 's and exactly 6 of sets Yi 's, then n is equal to :
(1) 45
(2) 15
(3) 50
(4) 30
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Correct answer is 30
EXplaination:
n(Xi) = 10. Ui = 1 Xi for i ∈ 50 = T,
n (T) = 500 each element of T belongs to exactly 20 elements of
Xi = 500/20 = 25 distinct elements
So 5n/6 = 25
n = 30
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