0 votes
142 views
in Chapter13:AC Circuits by (2.2k points)
edited
The total impedance of a circuit decreases when a capacitor is added in series with L and R. Explain why ?

1 Answer

0 votes
by (2.2k points)
edited

For an LR circuit, the impedance,
ZLR = \(\sqrt{R^{2}+X_{\mathrm{L}}^{2}}\), where XL is the reactance of the inductor.
When a capacitor of capacitance C is added in series with L and R, the impedance,
ZLCR = \(\sqrt{R^{2}+\left(X_{\mathrm{L}}-X_{\mathrm{C}}\right)^{2}}\) because in the case of an inductor the current lags behind the voltage by a phase angle of \(\frac{\pi}{2}\) rad while in the case of a capacitor the current leads the voltage by a phase angle of \(\frac{\pi}{2}\) rad. The decrease in net reactance decreases the total impedance (ZLCR < ZLR).

Related questions

Doubtly is an online community for engineering students, offering:

  • Free viva questions PDFs
  • Previous year question papers (PYQs)
  • Academic doubt solutions
  • Expert-guided solutions

Get the pro version for free by logging in!

5.7k questions

5.1k answers

108 comments

561 users

...