If α=cos-1(3/5) , β=tan-1(1/3), where 0<α,β<π/4 , then α-β is equal to
A) \(\sin^{-1} {9\over5\sqrt{10}}\)
B)\(\tan^{-1} ({9\over14})\)
C)\(\cos^{-1} {9\over5\sqrt{10}}\)
D)\(\tan^{-1} ({9\over5\sqrt{10}})\)
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Correct answer is A) \(\sin^{-1} {9\over5\sqrt{10}}\)
Detailed answer
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