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In a parallel plate capacitor with air between the plates, each plate has an area of 6 x 10-3 m2 and the distance between the plates is 3 mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100 V supply, what is the charge on each plate of the capacitor?

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A = 6 x 10-3 m2
d = 3 mm = 3 x 10-3m
C = \(\frac{\varepsilon_{0} \mathrm{~A}}{\mathrm{~d}}\)
= \(\frac{8.85 \times 10^{-12} \times 6 \times 10^{-3}}{3 \times 10^{-3}}\)
= 17.70 x 10-12
= 17.7 pF
Q = CV = 17.7 x 10-12 x 100
= 17.7 x 10-9C
= 1.77 nC

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