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A dice is tossed thrice. Find the probability of getting an odd number at least once?

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If a dice is thrown and an odd number occurs, then it may result in 1, 3, 5.

∴ The probability of getting an odd number in a throw of a dice

= \(\frac{3}{6}\) = \(\frac{1}{2}\).

∴ Probability of getting an even number = \(\frac{1}{2}\).

Now the probability of getting no odd number in a throw of dice 3 times

= Probability of getting an even number in a throw of a dice 3 times

= \(\frac{1}{2}\) × \(\frac{1}{2}\) × \(\frac{1}{2}\) = \(\frac{1}{8}\).

∴ Probability of getting at least one odd number in a throw of a dice 3 times

= 1 – \(\frac{1}{8}\) = \(\frac{7}{8}\)

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