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q1 = 0.4 μC = 0.4 x 10-6 C, q2 = – 0.8μC = – 0 .8 x 10-6 C, F = 0.2 N
(a) F = 9 x 109 r2 = 9 x 109 x \(\frac{\mathrm{q}_{1} \mathrm{q}_{2}}{\mathrm{~F}}\) = \(\frac{9 \times 10^{9} \times 0.4 \times 10^{-6} \times 0.8 \times 10^{-6}}{0.2}\) = 14.4 x 10-3 = 144 x 10-4m2 r = 12 x 10-2m
(b) 0.2 N, attractive.
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