Question

Calculate the temperature of 5.0 mol of a gas occupying 5 dm³ at 3.32 bar.
(R = 0.083 bar dm³ K^-1 mol^-1)

Answer 1

Given: n = number of moles = 5.0 mol, V = volume = 5 dm³
P = pressure = 3.32 bar, R = 0.083 bar dm³ K^-1 mol^-1
To find: Temperature (T)
Formula: PV = nRT
Calculation: According to ideal gas equation,
PV = nRT
∴ T = \(\frac{\mathrm{PV}}{\mathrm{nR}}=\frac{3.32 \times 5}{5.0 \times 0.083}\) = 40 K
Ans: The temperature of the gas is 40 K.